3.6.97 \(\int \frac {(a+b x)^{3/2} (c+d x)^{5/2}}{x^4} \, dx\)

Optimal. Leaf size=292 \[ \frac {d \sqrt {a+b x} \sqrt {c+d x} \left (5 a^2 d^2+26 a b c d+b^2 c^2\right )}{8 a c}+\frac {\left (-5 a^3 d^3-45 a^2 b c d^2-15 a b^2 c^2 d+b^3 c^3\right ) \tanh ^{-1}\left (\frac {\sqrt {c} \sqrt {a+b x}}{\sqrt {a} \sqrt {c+d x}}\right )}{8 a^{3/2} \sqrt {c}}-\frac {\sqrt {a+b x} (c+d x)^{3/2} \left (\frac {3 b^2 c}{a}+\frac {5 a d^2}{c}+40 b d\right )}{24 x}+\sqrt {b} d^{3/2} (3 a d+5 b c) \tanh ^{-1}\left (\frac {\sqrt {d} \sqrt {a+b x}}{\sqrt {b} \sqrt {c+d x}}\right )-\frac {(a+b x)^{3/2} (c+d x)^{5/2}}{3 x^3}-\frac {\sqrt {a+b x} (c+d x)^{5/2} (5 a d+3 b c)}{12 c x^2} \]

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Rubi [A]  time = 0.33, antiderivative size = 292, normalized size of antiderivative = 1.00, number of steps used = 10, number of rules used = 9, integrand size = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.409, Rules used = {97, 149, 154, 157, 63, 217, 206, 93, 208} \begin {gather*} \frac {d \sqrt {a+b x} \sqrt {c+d x} \left (5 a^2 d^2+26 a b c d+b^2 c^2\right )}{8 a c}+\frac {\left (-45 a^2 b c d^2-5 a^3 d^3-15 a b^2 c^2 d+b^3 c^3\right ) \tanh ^{-1}\left (\frac {\sqrt {c} \sqrt {a+b x}}{\sqrt {a} \sqrt {c+d x}}\right )}{8 a^{3/2} \sqrt {c}}-\frac {\sqrt {a+b x} (c+d x)^{3/2} \left (\frac {3 b^2 c}{a}+\frac {5 a d^2}{c}+40 b d\right )}{24 x}+\sqrt {b} d^{3/2} (3 a d+5 b c) \tanh ^{-1}\left (\frac {\sqrt {d} \sqrt {a+b x}}{\sqrt {b} \sqrt {c+d x}}\right )-\frac {(a+b x)^{3/2} (c+d x)^{5/2}}{3 x^3}-\frac {\sqrt {a+b x} (c+d x)^{5/2} (5 a d+3 b c)}{12 c x^2} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[((a + b*x)^(3/2)*(c + d*x)^(5/2))/x^4,x]

[Out]

(d*(b^2*c^2 + 26*a*b*c*d + 5*a^2*d^2)*Sqrt[a + b*x]*Sqrt[c + d*x])/(8*a*c) - (((3*b^2*c)/a + 40*b*d + (5*a*d^2
)/c)*Sqrt[a + b*x]*(c + d*x)^(3/2))/(24*x) - ((3*b*c + 5*a*d)*Sqrt[a + b*x]*(c + d*x)^(5/2))/(12*c*x^2) - ((a
+ b*x)^(3/2)*(c + d*x)^(5/2))/(3*x^3) + ((b^3*c^3 - 15*a*b^2*c^2*d - 45*a^2*b*c*d^2 - 5*a^3*d^3)*ArcTanh[(Sqrt
[c]*Sqrt[a + b*x])/(Sqrt[a]*Sqrt[c + d*x])])/(8*a^(3/2)*Sqrt[c]) + Sqrt[b]*d^(3/2)*(5*b*c + 3*a*d)*ArcTanh[(Sq
rt[d]*Sqrt[a + b*x])/(Sqrt[b]*Sqrt[c + d*x])]

Rule 63

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - (a*d)/b + (d*x^p)/b)^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]

Rule 93

Int[(((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_))/((e_.) + (f_.)*(x_)), x_Symbol] :> With[{q = Denomin
ator[m]}, Dist[q, Subst[Int[x^(q*(m + 1) - 1)/(b*e - a*f - (d*e - c*f)*x^q), x], x, (a + b*x)^(1/q)/(c + d*x)^
(1/q)], x]] /; FreeQ[{a, b, c, d, e, f}, x] && EqQ[m + n + 1, 0] && RationalQ[n] && LtQ[-1, m, 0] && SimplerQ[
a + b*x, c + d*x]

Rule 97

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[((a + b
*x)^(m + 1)*(c + d*x)^n*(e + f*x)^p)/(b*(m + 1)), x] - Dist[1/(b*(m + 1)), Int[(a + b*x)^(m + 1)*(c + d*x)^(n
- 1)*(e + f*x)^(p - 1)*Simp[d*e*n + c*f*p + d*f*(n + p)*x, x], x], x] /; FreeQ[{a, b, c, d, e, f}, x] && LtQ[m
, -1] && GtQ[n, 0] && GtQ[p, 0] && (IntegersQ[2*m, 2*n, 2*p] || IntegersQ[m, n + p] || IntegersQ[p, m + n])

Rule 149

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_))^(p_)*((g_.) + (h_.)*(x_)), x_Symb
ol] :> Simp[((b*g - a*h)*(a + b*x)^(m + 1)*(c + d*x)^n*(e + f*x)^(p + 1))/(b*(b*e - a*f)*(m + 1)), x] - Dist[1
/(b*(b*e - a*f)*(m + 1)), Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1)*(e + f*x)^p*Simp[b*c*(f*g - e*h)*(m + 1) + (
b*g - a*h)*(d*e*n + c*f*(p + 1)) + d*(b*(f*g - e*h)*(m + 1) + f*(b*g - a*h)*(n + p + 1))*x, x], x], x] /; Free
Q[{a, b, c, d, e, f, g, h, p}, x] && LtQ[m, -1] && GtQ[n, 0] && IntegerQ[m]

Rule 154

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_))^(p_)*((g_.) + (h_.)*(x_)), x_Symb
ol] :> Simp[(h*(a + b*x)^m*(c + d*x)^(n + 1)*(e + f*x)^(p + 1))/(d*f*(m + n + p + 2)), x] + Dist[1/(d*f*(m + n
+ p + 2)), Int[(a + b*x)^(m - 1)*(c + d*x)^n*(e + f*x)^p*Simp[a*d*f*g*(m + n + p + 2) - h*(b*c*e*m + a*(d*e*(
n + 1) + c*f*(p + 1))) + (b*d*f*g*(m + n + p + 2) + h*(a*d*f*m - b*(d*e*(m + n + 1) + c*f*(m + p + 1))))*x, x]
, x], x] /; FreeQ[{a, b, c, d, e, f, g, h, n, p}, x] && GtQ[m, 0] && NeQ[m + n + p + 2, 0] && IntegersQ[2*m, 2
*n, 2*p]

Rule 157

Int[(((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_))^(p_)*((g_.) + (h_.)*(x_)))/((a_.) + (b_.)*(x_)), x_Symbol]
:> Dist[h/b, Int[(c + d*x)^n*(e + f*x)^p, x], x] + Dist[(b*g - a*h)/b, Int[((c + d*x)^n*(e + f*x)^p)/(a + b*x
), x], x] /; FreeQ[{a, b, c, d, e, f, g, h, n, p}, x]

Rule 206

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTanh[(Rt[-b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[-b, 2]), x]
/; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rule 208

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-(a/b), 2]*ArcTanh[x/Rt[-(a/b), 2]])/a, x] /; FreeQ[{a,
b}, x] && NegQ[a/b]

Rule 217

Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Subst[Int[1/(1 - b*x^2), x], x, x/Sqrt[a + b*x^2]] /; FreeQ[{a,
b}, x] &&  !GtQ[a, 0]

Rubi steps

\begin {align*} \int \frac {(a+b x)^{3/2} (c+d x)^{5/2}}{x^4} \, dx &=-\frac {(a+b x)^{3/2} (c+d x)^{5/2}}{3 x^3}+\frac {1}{3} \int \frac {\sqrt {a+b x} (c+d x)^{3/2} \left (\frac {1}{2} (3 b c+5 a d)+4 b d x\right )}{x^3} \, dx\\ &=-\frac {(3 b c+5 a d) \sqrt {a+b x} (c+d x)^{5/2}}{12 c x^2}-\frac {(a+b x)^{3/2} (c+d x)^{5/2}}{3 x^3}+\frac {\int \frac {(c+d x)^{3/2} \left (\frac {1}{4} \left (3 b^2 c^2+40 a b c d+5 a^2 d^2\right )+\frac {1}{2} b d (19 b c+5 a d) x\right )}{x^2 \sqrt {a+b x}} \, dx}{6 c}\\ &=-\frac {\left (\frac {3 b^2 c}{a}+40 b d+\frac {5 a d^2}{c}\right ) \sqrt {a+b x} (c+d x)^{3/2}}{24 x}-\frac {(3 b c+5 a d) \sqrt {a+b x} (c+d x)^{5/2}}{12 c x^2}-\frac {(a+b x)^{3/2} (c+d x)^{5/2}}{3 x^3}+\frac {\int \frac {\sqrt {c+d x} \left (-\frac {3}{8} \left (b^3 c^3-15 a b^2 c^2 d-45 a^2 b c d^2-5 a^3 d^3\right )+\frac {3}{4} b d \left (b^2 c^2+26 a b c d+5 a^2 d^2\right ) x\right )}{x \sqrt {a+b x}} \, dx}{6 a c}\\ &=\frac {d \left (b^2 c^2+26 a b c d+5 a^2 d^2\right ) \sqrt {a+b x} \sqrt {c+d x}}{8 a c}-\frac {\left (\frac {3 b^2 c}{a}+40 b d+\frac {5 a d^2}{c}\right ) \sqrt {a+b x} (c+d x)^{3/2}}{24 x}-\frac {(3 b c+5 a d) \sqrt {a+b x} (c+d x)^{5/2}}{12 c x^2}-\frac {(a+b x)^{3/2} (c+d x)^{5/2}}{3 x^3}+\frac {\int \frac {-\frac {3}{8} b c \left (b^3 c^3-15 a b^2 c^2 d-45 a^2 b c d^2-5 a^3 d^3\right )+3 a b^2 c d^2 (5 b c+3 a d) x}{x \sqrt {a+b x} \sqrt {c+d x}} \, dx}{6 a b c}\\ &=\frac {d \left (b^2 c^2+26 a b c d+5 a^2 d^2\right ) \sqrt {a+b x} \sqrt {c+d x}}{8 a c}-\frac {\left (\frac {3 b^2 c}{a}+40 b d+\frac {5 a d^2}{c}\right ) \sqrt {a+b x} (c+d x)^{3/2}}{24 x}-\frac {(3 b c+5 a d) \sqrt {a+b x} (c+d x)^{5/2}}{12 c x^2}-\frac {(a+b x)^{3/2} (c+d x)^{5/2}}{3 x^3}+\frac {1}{2} \left (b d^2 (5 b c+3 a d)\right ) \int \frac {1}{\sqrt {a+b x} \sqrt {c+d x}} \, dx-\frac {\left (b^3 c^3-15 a b^2 c^2 d-45 a^2 b c d^2-5 a^3 d^3\right ) \int \frac {1}{x \sqrt {a+b x} \sqrt {c+d x}} \, dx}{16 a}\\ &=\frac {d \left (b^2 c^2+26 a b c d+5 a^2 d^2\right ) \sqrt {a+b x} \sqrt {c+d x}}{8 a c}-\frac {\left (\frac {3 b^2 c}{a}+40 b d+\frac {5 a d^2}{c}\right ) \sqrt {a+b x} (c+d x)^{3/2}}{24 x}-\frac {(3 b c+5 a d) \sqrt {a+b x} (c+d x)^{5/2}}{12 c x^2}-\frac {(a+b x)^{3/2} (c+d x)^{5/2}}{3 x^3}+\left (d^2 (5 b c+3 a d)\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {c-\frac {a d}{b}+\frac {d x^2}{b}}} \, dx,x,\sqrt {a+b x}\right )-\frac {\left (b^3 c^3-15 a b^2 c^2 d-45 a^2 b c d^2-5 a^3 d^3\right ) \operatorname {Subst}\left (\int \frac {1}{-a+c x^2} \, dx,x,\frac {\sqrt {a+b x}}{\sqrt {c+d x}}\right )}{8 a}\\ &=\frac {d \left (b^2 c^2+26 a b c d+5 a^2 d^2\right ) \sqrt {a+b x} \sqrt {c+d x}}{8 a c}-\frac {\left (\frac {3 b^2 c}{a}+40 b d+\frac {5 a d^2}{c}\right ) \sqrt {a+b x} (c+d x)^{3/2}}{24 x}-\frac {(3 b c+5 a d) \sqrt {a+b x} (c+d x)^{5/2}}{12 c x^2}-\frac {(a+b x)^{3/2} (c+d x)^{5/2}}{3 x^3}+\frac {\left (b^3 c^3-15 a b^2 c^2 d-45 a^2 b c d^2-5 a^3 d^3\right ) \tanh ^{-1}\left (\frac {\sqrt {c} \sqrt {a+b x}}{\sqrt {a} \sqrt {c+d x}}\right )}{8 a^{3/2} \sqrt {c}}+\left (d^2 (5 b c+3 a d)\right ) \operatorname {Subst}\left (\int \frac {1}{1-\frac {d x^2}{b}} \, dx,x,\frac {\sqrt {a+b x}}{\sqrt {c+d x}}\right )\\ &=\frac {d \left (b^2 c^2+26 a b c d+5 a^2 d^2\right ) \sqrt {a+b x} \sqrt {c+d x}}{8 a c}-\frac {\left (\frac {3 b^2 c}{a}+40 b d+\frac {5 a d^2}{c}\right ) \sqrt {a+b x} (c+d x)^{3/2}}{24 x}-\frac {(3 b c+5 a d) \sqrt {a+b x} (c+d x)^{5/2}}{12 c x^2}-\frac {(a+b x)^{3/2} (c+d x)^{5/2}}{3 x^3}+\frac {\left (b^3 c^3-15 a b^2 c^2 d-45 a^2 b c d^2-5 a^3 d^3\right ) \tanh ^{-1}\left (\frac {\sqrt {c} \sqrt {a+b x}}{\sqrt {a} \sqrt {c+d x}}\right )}{8 a^{3/2} \sqrt {c}}+\sqrt {b} d^{3/2} (5 b c+3 a d) \tanh ^{-1}\left (\frac {\sqrt {d} \sqrt {a+b x}}{\sqrt {b} \sqrt {c+d x}}\right )\\ \end {align*}

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Mathematica [A]  time = 2.97, size = 254, normalized size = 0.87 \begin {gather*} -\frac {\sqrt {a+b x} \sqrt {c+d x} \left (a^2 \left (8 c^2+26 c d x+33 d^2 x^2\right )+2 a b x \left (7 c^2+34 c d x-12 d^2 x^2\right )+3 b^2 c^2 x^2\right )}{24 a x^3}-\frac {\left (5 a^3 d^3+45 a^2 b c d^2+15 a b^2 c^2 d-b^3 c^3\right ) \tanh ^{-1}\left (\frac {\sqrt {c} \sqrt {a+b x}}{\sqrt {a} \sqrt {c+d x}}\right )}{8 a^{3/2} \sqrt {c}}+\frac {d^{3/2} \sqrt {b c-a d} (3 a d+5 b c) \sqrt {\frac {b (c+d x)}{b c-a d}} \sinh ^{-1}\left (\frac {\sqrt {d} \sqrt {a+b x}}{\sqrt {b c-a d}}\right )}{\sqrt {c+d x}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[((a + b*x)^(3/2)*(c + d*x)^(5/2))/x^4,x]

[Out]

-1/24*(Sqrt[a + b*x]*Sqrt[c + d*x]*(3*b^2*c^2*x^2 + 2*a*b*x*(7*c^2 + 34*c*d*x - 12*d^2*x^2) + a^2*(8*c^2 + 26*
c*d*x + 33*d^2*x^2)))/(a*x^3) + (d^(3/2)*Sqrt[b*c - a*d]*(5*b*c + 3*a*d)*Sqrt[(b*(c + d*x))/(b*c - a*d)]*ArcSi
nh[(Sqrt[d]*Sqrt[a + b*x])/Sqrt[b*c - a*d]])/Sqrt[c + d*x] - ((-(b^3*c^3) + 15*a*b^2*c^2*d + 45*a^2*b*c*d^2 +
5*a^3*d^3)*ArcTanh[(Sqrt[c]*Sqrt[a + b*x])/(Sqrt[a]*Sqrt[c + d*x])])/(8*a^(3/2)*Sqrt[c])

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IntegrateAlgebraic [B]  time = 0.78, size = 585, normalized size = 2.00 \begin {gather*} \frac {\left (-5 a^3 d^3-45 a^2 b c d^2-15 a b^2 c^2 d+b^3 c^3\right ) \tanh ^{-1}\left (\frac {\sqrt {a} \sqrt {c+d x}}{\sqrt {c} \sqrt {a+b x}}\right )}{8 a^{3/2} \sqrt {c}}-\frac {\sqrt {c+d x} \left (-\frac {33 a^5 d^4 (c+d x)^2}{(a+b x)^2}+\frac {57 a^5 b d^3 (c+d x)^3}{(a+b x)^3}-\frac {15 a^4 b^2 c d^2 (c+d x)^3}{(a+b x)^3}+\frac {40 a^4 c d^4 (c+d x)}{a+b x}-\frac {121 a^4 b c d^3 (c+d x)^2}{(a+b x)^2}-\frac {45 a^3 b^3 c^2 d (c+d x)^3}{(a+b x)^3}+\frac {45 a^3 b^2 c^2 d^2 (c+d x)^2}{(a+b x)^2}+\frac {159 a^3 b c^2 d^3 (c+d x)}{a+b x}-15 a^3 c^2 d^4+\frac {3 a^2 b^4 c^3 (c+d x)^3}{(a+b x)^3}+\frac {117 a^2 b^3 c^3 d (c+d x)^2}{(a+b x)^2}-\frac {153 a^2 b^2 c^3 d^2 (c+d x)}{a+b x}-63 a^2 b c^3 d^3-\frac {3 b^4 c^5 (c+d x)}{a+b x}-\frac {8 a b^4 c^4 (c+d x)^2}{(a+b x)^2}-\frac {43 a b^3 c^4 d (c+d x)}{a+b x}+75 a b^2 c^4 d^2+3 b^3 c^5 d\right )}{24 a \sqrt {a+b x} \left (\frac {a (c+d x)}{a+b x}-c\right )^3 \left (\frac {b (c+d x)}{a+b x}-d\right )}+\left (3 a \sqrt {b} d^{5/2}+5 b^{3/2} c d^{3/2}\right ) \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {c+d x}}{\sqrt {d} \sqrt {a+b x}}\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[((a + b*x)^(3/2)*(c + d*x)^(5/2))/x^4,x]

[Out]

-1/24*(Sqrt[c + d*x]*(3*b^3*c^5*d + 75*a*b^2*c^4*d^2 - 63*a^2*b*c^3*d^3 - 15*a^3*c^2*d^4 - (3*b^4*c^5*(c + d*x
))/(a + b*x) - (43*a*b^3*c^4*d*(c + d*x))/(a + b*x) - (153*a^2*b^2*c^3*d^2*(c + d*x))/(a + b*x) + (159*a^3*b*c
^2*d^3*(c + d*x))/(a + b*x) + (40*a^4*c*d^4*(c + d*x))/(a + b*x) - (8*a*b^4*c^4*(c + d*x)^2)/(a + b*x)^2 + (11
7*a^2*b^3*c^3*d*(c + d*x)^2)/(a + b*x)^2 + (45*a^3*b^2*c^2*d^2*(c + d*x)^2)/(a + b*x)^2 - (121*a^4*b*c*d^3*(c
+ d*x)^2)/(a + b*x)^2 - (33*a^5*d^4*(c + d*x)^2)/(a + b*x)^2 + (3*a^2*b^4*c^3*(c + d*x)^3)/(a + b*x)^3 - (45*a
^3*b^3*c^2*d*(c + d*x)^3)/(a + b*x)^3 - (15*a^4*b^2*c*d^2*(c + d*x)^3)/(a + b*x)^3 + (57*a^5*b*d^3*(c + d*x)^3
)/(a + b*x)^3))/(a*Sqrt[a + b*x]*(-c + (a*(c + d*x))/(a + b*x))^3*(-d + (b*(c + d*x))/(a + b*x))) + ((b^3*c^3
- 15*a*b^2*c^2*d - 45*a^2*b*c*d^2 - 5*a^3*d^3)*ArcTanh[(Sqrt[a]*Sqrt[c + d*x])/(Sqrt[c]*Sqrt[a + b*x])])/(8*a^
(3/2)*Sqrt[c]) + (5*b^(3/2)*c*d^(3/2) + 3*a*Sqrt[b]*d^(5/2))*ArcTanh[(Sqrt[b]*Sqrt[c + d*x])/(Sqrt[d]*Sqrt[a +
b*x])]

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fricas [A]  time = 12.55, size = 1353, normalized size = 4.63

result too large to display

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^(3/2)*(d*x+c)^(5/2)/x^4,x, algorithm="fricas")

[Out]

[1/96*(24*(5*a^2*b*c^2*d + 3*a^3*c*d^2)*sqrt(b*d)*x^3*log(8*b^2*d^2*x^2 + b^2*c^2 + 6*a*b*c*d + a^2*d^2 + 4*(2
*b*d*x + b*c + a*d)*sqrt(b*d)*sqrt(b*x + a)*sqrt(d*x + c) + 8*(b^2*c*d + a*b*d^2)*x) - 3*(b^3*c^3 - 15*a*b^2*c
^2*d - 45*a^2*b*c*d^2 - 5*a^3*d^3)*sqrt(a*c)*x^3*log((8*a^2*c^2 + (b^2*c^2 + 6*a*b*c*d + a^2*d^2)*x^2 - 4*(2*a
*c + (b*c + a*d)*x)*sqrt(a*c)*sqrt(b*x + a)*sqrt(d*x + c) + 8*(a*b*c^2 + a^2*c*d)*x)/x^2) + 4*(24*a^2*b*c*d^2*
x^3 - 8*a^3*c^3 - (3*a*b^2*c^3 + 68*a^2*b*c^2*d + 33*a^3*c*d^2)*x^2 - 2*(7*a^2*b*c^3 + 13*a^3*c^2*d)*x)*sqrt(b
*x + a)*sqrt(d*x + c))/(a^2*c*x^3), -1/96*(48*(5*a^2*b*c^2*d + 3*a^3*c*d^2)*sqrt(-b*d)*x^3*arctan(1/2*(2*b*d*x
+ b*c + a*d)*sqrt(-b*d)*sqrt(b*x + a)*sqrt(d*x + c)/(b^2*d^2*x^2 + a*b*c*d + (b^2*c*d + a*b*d^2)*x)) + 3*(b^3
*c^3 - 15*a*b^2*c^2*d - 45*a^2*b*c*d^2 - 5*a^3*d^3)*sqrt(a*c)*x^3*log((8*a^2*c^2 + (b^2*c^2 + 6*a*b*c*d + a^2*
d^2)*x^2 - 4*(2*a*c + (b*c + a*d)*x)*sqrt(a*c)*sqrt(b*x + a)*sqrt(d*x + c) + 8*(a*b*c^2 + a^2*c*d)*x)/x^2) - 4
*(24*a^2*b*c*d^2*x^3 - 8*a^3*c^3 - (3*a*b^2*c^3 + 68*a^2*b*c^2*d + 33*a^3*c*d^2)*x^2 - 2*(7*a^2*b*c^3 + 13*a^3
*c^2*d)*x)*sqrt(b*x + a)*sqrt(d*x + c))/(a^2*c*x^3), -1/48*(3*(b^3*c^3 - 15*a*b^2*c^2*d - 45*a^2*b*c*d^2 - 5*a
^3*d^3)*sqrt(-a*c)*x^3*arctan(1/2*(2*a*c + (b*c + a*d)*x)*sqrt(-a*c)*sqrt(b*x + a)*sqrt(d*x + c)/(a*b*c*d*x^2
+ a^2*c^2 + (a*b*c^2 + a^2*c*d)*x)) - 12*(5*a^2*b*c^2*d + 3*a^3*c*d^2)*sqrt(b*d)*x^3*log(8*b^2*d^2*x^2 + b^2*c
^2 + 6*a*b*c*d + a^2*d^2 + 4*(2*b*d*x + b*c + a*d)*sqrt(b*d)*sqrt(b*x + a)*sqrt(d*x + c) + 8*(b^2*c*d + a*b*d^
2)*x) - 2*(24*a^2*b*c*d^2*x^3 - 8*a^3*c^3 - (3*a*b^2*c^3 + 68*a^2*b*c^2*d + 33*a^3*c*d^2)*x^2 - 2*(7*a^2*b*c^3
+ 13*a^3*c^2*d)*x)*sqrt(b*x + a)*sqrt(d*x + c))/(a^2*c*x^3), -1/48*(3*(b^3*c^3 - 15*a*b^2*c^2*d - 45*a^2*b*c*
d^2 - 5*a^3*d^3)*sqrt(-a*c)*x^3*arctan(1/2*(2*a*c + (b*c + a*d)*x)*sqrt(-a*c)*sqrt(b*x + a)*sqrt(d*x + c)/(a*b
*c*d*x^2 + a^2*c^2 + (a*b*c^2 + a^2*c*d)*x)) + 24*(5*a^2*b*c^2*d + 3*a^3*c*d^2)*sqrt(-b*d)*x^3*arctan(1/2*(2*b
*d*x + b*c + a*d)*sqrt(-b*d)*sqrt(b*x + a)*sqrt(d*x + c)/(b^2*d^2*x^2 + a*b*c*d + (b^2*c*d + a*b*d^2)*x)) - 2*
(24*a^2*b*c*d^2*x^3 - 8*a^3*c^3 - (3*a*b^2*c^3 + 68*a^2*b*c^2*d + 33*a^3*c*d^2)*x^2 - 2*(7*a^2*b*c^3 + 13*a^3*
c^2*d)*x)*sqrt(b*x + a)*sqrt(d*x + c))/(a^2*c*x^3)]

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giac [B]  time = 100.93, size = 2316, normalized size = 7.93

result too large to display

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^(3/2)*(d*x+c)^(5/2)/x^4,x, algorithm="giac")

[Out]

1/24*(24*sqrt(b^2*c + (b*x + a)*b*d - a*b*d)*sqrt(b*x + a)*d^2*abs(b) - 12*(5*sqrt(b*d)*b*c*d*abs(b) + 3*sqrt(
b*d)*a*d^2*abs(b))*log((sqrt(b*d)*sqrt(b*x + a) - sqrt(b^2*c + (b*x + a)*b*d - a*b*d))^2) + 3*(sqrt(b*d)*b^4*c
^3*abs(b) - 15*sqrt(b*d)*a*b^3*c^2*d*abs(b) - 45*sqrt(b*d)*a^2*b^2*c*d^2*abs(b) - 5*sqrt(b*d)*a^3*b*d^3*abs(b)
)*arctan(-1/2*(b^2*c + a*b*d - (sqrt(b*d)*sqrt(b*x + a) - sqrt(b^2*c + (b*x + a)*b*d - a*b*d))^2)/(sqrt(-a*b*c
*d)*b))/(sqrt(-a*b*c*d)*a*b) - 2*(3*sqrt(b*d)*b^14*c^8*abs(b) + 50*sqrt(b*d)*a*b^13*c^7*d*abs(b) - 330*sqrt(b*
d)*a^2*b^12*c^6*d^2*abs(b) + 762*sqrt(b*d)*a^3*b^11*c^5*d^3*abs(b) - 820*sqrt(b*d)*a^4*b^10*c^4*d^4*abs(b) + 3
42*sqrt(b*d)*a^5*b^9*c^3*d^5*abs(b) + 90*sqrt(b*d)*a^6*b^8*c^2*d^6*abs(b) - 130*sqrt(b*d)*a^7*b^7*c*d^7*abs(b)
+ 33*sqrt(b*d)*a^8*b^6*d^8*abs(b) - 15*sqrt(b*d)*(sqrt(b*d)*sqrt(b*x + a) - sqrt(b^2*c + (b*x + a)*b*d - a*b*
d))^2*b^12*c^7*abs(b) - 267*sqrt(b*d)*(sqrt(b*d)*sqrt(b*x + a) - sqrt(b^2*c + (b*x + a)*b*d - a*b*d))^2*a*b^11
*c^6*d*abs(b) + 765*sqrt(b*d)*(sqrt(b*d)*sqrt(b*x + a) - sqrt(b^2*c + (b*x + a)*b*d - a*b*d))^2*a^2*b^10*c^5*d
^2*abs(b) - 255*sqrt(b*d)*(sqrt(b*d)*sqrt(b*x + a) - sqrt(b^2*c + (b*x + a)*b*d - a*b*d))^2*a^3*b^9*c^4*d^3*ab
s(b) - 765*sqrt(b*d)*(sqrt(b*d)*sqrt(b*x + a) - sqrt(b^2*c + (b*x + a)*b*d - a*b*d))^2*a^4*b^8*c^3*d^4*abs(b)
+ 495*sqrt(b*d)*(sqrt(b*d)*sqrt(b*x + a) - sqrt(b^2*c + (b*x + a)*b*d - a*b*d))^2*a^5*b^7*c^2*d^5*abs(b) + 207
*sqrt(b*d)*(sqrt(b*d)*sqrt(b*x + a) - sqrt(b^2*c + (b*x + a)*b*d - a*b*d))^2*a^6*b^6*c*d^6*abs(b) - 165*sqrt(b
*d)*(sqrt(b*d)*sqrt(b*x + a) - sqrt(b^2*c + (b*x + a)*b*d - a*b*d))^2*a^7*b^5*d^7*abs(b) + 30*sqrt(b*d)*(sqrt(
b*d)*sqrt(b*x + a) - sqrt(b^2*c + (b*x + a)*b*d - a*b*d))^4*b^10*c^6*abs(b) + 600*sqrt(b*d)*(sqrt(b*d)*sqrt(b*
x + a) - sqrt(b^2*c + (b*x + a)*b*d - a*b*d))^4*a*b^9*c^5*d*abs(b) - 210*sqrt(b*d)*(sqrt(b*d)*sqrt(b*x + a) -
sqrt(b^2*c + (b*x + a)*b*d - a*b*d))^4*a^2*b^8*c^4*d^2*abs(b) - 528*sqrt(b*d)*(sqrt(b*d)*sqrt(b*x + a) - sqrt(
b^2*c + (b*x + a)*b*d - a*b*d))^4*a^3*b^7*c^3*d^3*abs(b) - 534*sqrt(b*d)*(sqrt(b*d)*sqrt(b*x + a) - sqrt(b^2*c
+ (b*x + a)*b*d - a*b*d))^4*a^4*b^6*c^2*d^4*abs(b) + 312*sqrt(b*d)*(sqrt(b*d)*sqrt(b*x + a) - sqrt(b^2*c + (b
*x + a)*b*d - a*b*d))^4*a^5*b^5*c*d^5*abs(b) + 330*sqrt(b*d)*(sqrt(b*d)*sqrt(b*x + a) - sqrt(b^2*c + (b*x + a)
*b*d - a*b*d))^4*a^6*b^4*d^6*abs(b) - 30*sqrt(b*d)*(sqrt(b*d)*sqrt(b*x + a) - sqrt(b^2*c + (b*x + a)*b*d - a*b
*d))^6*b^8*c^5*abs(b) - 698*sqrt(b*d)*(sqrt(b*d)*sqrt(b*x + a) - sqrt(b^2*c + (b*x + a)*b*d - a*b*d))^6*a*b^7*
c^4*d*abs(b) - 756*sqrt(b*d)*(sqrt(b*d)*sqrt(b*x + a) - sqrt(b^2*c + (b*x + a)*b*d - a*b*d))^6*a^2*b^6*c^3*d^2
*abs(b) - 636*sqrt(b*d)*(sqrt(b*d)*sqrt(b*x + a) - sqrt(b^2*c + (b*x + a)*b*d - a*b*d))^6*a^3*b^5*c^2*d^3*abs(
b) - 878*sqrt(b*d)*(sqrt(b*d)*sqrt(b*x + a) - sqrt(b^2*c + (b*x + a)*b*d - a*b*d))^6*a^4*b^4*c*d^4*abs(b) - 33
0*sqrt(b*d)*(sqrt(b*d)*sqrt(b*x + a) - sqrt(b^2*c + (b*x + a)*b*d - a*b*d))^6*a^5*b^3*d^5*abs(b) + 15*sqrt(b*d
)*(sqrt(b*d)*sqrt(b*x + a) - sqrt(b^2*c + (b*x + a)*b*d - a*b*d))^8*b^6*c^4*abs(b) + 414*sqrt(b*d)*(sqrt(b*d)*
sqrt(b*x + a) - sqrt(b^2*c + (b*x + a)*b*d - a*b*d))^8*a*b^5*c^3*d*abs(b) + 684*sqrt(b*d)*(sqrt(b*d)*sqrt(b*x
+ a) - sqrt(b^2*c + (b*x + a)*b*d - a*b*d))^8*a^2*b^4*c^2*d^2*abs(b) + 642*sqrt(b*d)*(sqrt(b*d)*sqrt(b*x + a)
- sqrt(b^2*c + (b*x + a)*b*d - a*b*d))^8*a^3*b^3*c*d^3*abs(b) + 165*sqrt(b*d)*(sqrt(b*d)*sqrt(b*x + a) - sqrt(
b^2*c + (b*x + a)*b*d - a*b*d))^8*a^4*b^2*d^4*abs(b) - 3*sqrt(b*d)*(sqrt(b*d)*sqrt(b*x + a) - sqrt(b^2*c + (b*
x + a)*b*d - a*b*d))^10*b^4*c^3*abs(b) - 99*sqrt(b*d)*(sqrt(b*d)*sqrt(b*x + a) - sqrt(b^2*c + (b*x + a)*b*d -
a*b*d))^10*a*b^3*c^2*d*abs(b) - 153*sqrt(b*d)*(sqrt(b*d)*sqrt(b*x + a) - sqrt(b^2*c + (b*x + a)*b*d - a*b*d))^
10*a^2*b^2*c*d^2*abs(b) - 33*sqrt(b*d)*(sqrt(b*d)*sqrt(b*x + a) - sqrt(b^2*c + (b*x + a)*b*d - a*b*d))^10*a^3*
b*d^3*abs(b))/((b^4*c^2 - 2*a*b^3*c*d + a^2*b^2*d^2 - 2*(sqrt(b*d)*sqrt(b*x + a) - sqrt(b^2*c + (b*x + a)*b*d
- a*b*d))^2*b^2*c - 2*(sqrt(b*d)*sqrt(b*x + a) - sqrt(b^2*c + (b*x + a)*b*d - a*b*d))^2*a*b*d + (sqrt(b*d)*sqr
t(b*x + a) - sqrt(b^2*c + (b*x + a)*b*d - a*b*d))^4)^3*a))/b

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maple [B]  time = 0.02, size = 706, normalized size = 2.42 \begin {gather*} \frac {\sqrt {b x +a}\, \sqrt {d x +c}\, \left (-15 \sqrt {b d}\, a^{3} d^{3} x^{3} \ln \left (\frac {a d x +b c x +2 a c +2 \sqrt {a c}\, \sqrt {b d \,x^{2}+a d x +b c x +a c}}{x}\right )-135 \sqrt {b d}\, a^{2} b c \,d^{2} x^{3} \ln \left (\frac {a d x +b c x +2 a c +2 \sqrt {a c}\, \sqrt {b d \,x^{2}+a d x +b c x +a c}}{x}\right )+72 \sqrt {a c}\, a^{2} b \,d^{3} x^{3} \ln \left (\frac {2 b d x +a d +b c +2 \sqrt {b d \,x^{2}+a d x +b c x +a c}\, \sqrt {b d}}{2 \sqrt {b d}}\right )-45 \sqrt {b d}\, a \,b^{2} c^{2} d \,x^{3} \ln \left (\frac {a d x +b c x +2 a c +2 \sqrt {a c}\, \sqrt {b d \,x^{2}+a d x +b c x +a c}}{x}\right )+120 \sqrt {a c}\, a \,b^{2} c \,d^{2} x^{3} \ln \left (\frac {2 b d x +a d +b c +2 \sqrt {b d \,x^{2}+a d x +b c x +a c}\, \sqrt {b d}}{2 \sqrt {b d}}\right )+3 \sqrt {b d}\, b^{3} c^{3} x^{3} \ln \left (\frac {a d x +b c x +2 a c +2 \sqrt {a c}\, \sqrt {b d \,x^{2}+a d x +b c x +a c}}{x}\right )+48 \sqrt {b d \,x^{2}+a d x +b c x +a c}\, \sqrt {b d}\, \sqrt {a c}\, a b \,d^{2} x^{3}-66 \sqrt {b d \,x^{2}+a d x +b c x +a c}\, \sqrt {b d}\, \sqrt {a c}\, a^{2} d^{2} x^{2}-136 \sqrt {b d \,x^{2}+a d x +b c x +a c}\, \sqrt {b d}\, \sqrt {a c}\, a b c d \,x^{2}-6 \sqrt {b d \,x^{2}+a d x +b c x +a c}\, \sqrt {b d}\, \sqrt {a c}\, b^{2} c^{2} x^{2}-52 \sqrt {b d \,x^{2}+a d x +b c x +a c}\, \sqrt {b d}\, \sqrt {a c}\, a^{2} c d x -28 \sqrt {b d \,x^{2}+a d x +b c x +a c}\, \sqrt {b d}\, \sqrt {a c}\, a b \,c^{2} x -16 \sqrt {b d \,x^{2}+a d x +b c x +a c}\, \sqrt {b d}\, \sqrt {a c}\, a^{2} c^{2}\right )}{48 \sqrt {b d \,x^{2}+a d x +b c x +a c}\, \sqrt {b d}\, \sqrt {a c}\, a \,x^{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x+a)^(3/2)*(d*x+c)^(5/2)/x^4,x)

[Out]

1/48*(b*x+a)^(1/2)*(d*x+c)^(1/2)/a*(72*(a*c)^(1/2)*a^2*b*d^3*x^3*ln(1/2*(2*b*d*x+a*d+b*c+2*(b*d*x^2+a*d*x+b*c*
x+a*c)^(1/2)*(b*d)^(1/2))/(b*d)^(1/2))+120*(a*c)^(1/2)*a*b^2*c*d^2*x^3*ln(1/2*(2*b*d*x+a*d+b*c+2*(b*d*x^2+a*d*
x+b*c*x+a*c)^(1/2)*(b*d)^(1/2))/(b*d)^(1/2))-15*(b*d)^(1/2)*a^3*d^3*x^3*ln((a*d*x+b*c*x+2*a*c+2*(a*c)^(1/2)*(b
*d*x^2+a*d*x+b*c*x+a*c)^(1/2))/x)-135*(b*d)^(1/2)*a^2*b*c*d^2*x^3*ln((a*d*x+b*c*x+2*a*c+2*(a*c)^(1/2)*(b*d*x^2
+a*d*x+b*c*x+a*c)^(1/2))/x)-45*(b*d)^(1/2)*a*b^2*c^2*d*x^3*ln((a*d*x+b*c*x+2*a*c+2*(a*c)^(1/2)*(b*d*x^2+a*d*x+
b*c*x+a*c)^(1/2))/x)+3*(b*d)^(1/2)*b^3*c^3*x^3*ln((a*d*x+b*c*x+2*a*c+2*(a*c)^(1/2)*(b*d*x^2+a*d*x+b*c*x+a*c)^(
1/2))/x)+48*(b*d*x^2+a*d*x+b*c*x+a*c)^(1/2)*(b*d)^(1/2)*(a*c)^(1/2)*x^3*a*b*d^2-66*(b*d*x^2+a*d*x+b*c*x+a*c)^(
1/2)*(b*d)^(1/2)*(a*c)^(1/2)*a^2*d^2*x^2-136*(b*d*x^2+a*d*x+b*c*x+a*c)^(1/2)*(b*d)^(1/2)*(a*c)^(1/2)*a*b*c*d*x
^2-6*(b*d*x^2+a*d*x+b*c*x+a*c)^(1/2)*(b*d)^(1/2)*(a*c)^(1/2)*b^2*c^2*x^2-52*(b*d*x^2+a*d*x+b*c*x+a*c)^(1/2)*(b
*d)^(1/2)*(a*c)^(1/2)*a^2*c*d*x-28*(b*d*x^2+a*d*x+b*c*x+a*c)^(1/2)*(b*d)^(1/2)*(a*c)^(1/2)*a*b*c^2*x-16*(b*d*x
^2+a*d*x+b*c*x+a*c)^(1/2)*(b*d)^(1/2)*(a*c)^(1/2)*a^2*c^2)/(b*d*x^2+a*d*x+b*c*x+a*c)^(1/2)/x^3/(b*d)^(1/2)/(a*
c)^(1/2)

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maxima [F(-2)]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: ValueError} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^(3/2)*(d*x+c)^(5/2)/x^4,x, algorithm="maxima")

[Out]

Exception raised: ValueError >> Computation failed since Maxima requested additional constraints; using the 'a
ssume' command before evaluation *may* help (example of legal syntax is 'assume(a*d-b*c>0)', see `assume?` for
more details)Is a*d-b*c zero or nonzero?

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mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {{\left (a+b\,x\right )}^{3/2}\,{\left (c+d\,x\right )}^{5/2}}{x^4} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((a + b*x)^(3/2)*(c + d*x)^(5/2))/x^4,x)

[Out]

int(((a + b*x)^(3/2)*(c + d*x)^(5/2))/x^4, x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (a + b x\right )^{\frac {3}{2}} \left (c + d x\right )^{\frac {5}{2}}}{x^{4}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)**(3/2)*(d*x+c)**(5/2)/x**4,x)

[Out]

Integral((a + b*x)**(3/2)*(c + d*x)**(5/2)/x**4, x)

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